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If f '(x) = xx1x+x and f(1) = 52, then f(x) = log x + xx22 + ______

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Question

If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + ______

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Solution

If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + 2

Explanation:

f(x) = ∫f '(x) dx

`= int (1/"x" + "x")` dx

f(x) = log |x| + `"x"^2/2 + "c"`   ...(i)

f(1) = `5/2`

f(1) = log 1 + `1^2/2` + c

∴ `5/2 = 0 + 1/2 + "c"`   ...(∵ log 1 = 0)

∴ c = `5/2 - 1/2`

∴ = `4/2` = 2

∴ c = 2

∴ f(x) = log |x| + `"x"^2/2` + 2

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Notes

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Chapter 5: Integration - MISCELLANEOUS EXERCISE - 5 [Page 138]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q II. 3. | Page 138

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