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Question
Evaluate the following integrals:
`int (sin4x)/(cos2x).dx`
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Solution
`int (sin4x)/(cos2x).dx`
= `int(2sin 2x cos 2x)/(cos2x).dx`
= `2int sin 2x .dx`
= `2(-(cos2x)/2) + c`
= – cos 2x + c.
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