English

Evaluate: ∫x⋅e2x dx

Advertisements
Advertisements

Question

Evaluate: `int "x" * "e"^"2x"` dx

Sum
Advertisements

Solution

Let I = `int "x" * "e"^"2x"` dx

`= "x" int "e"^"2x" "dx" - int["d"/"dx" ("x") int "e"^"2x" * "dx"]` dx

`= "x" * "e"^"2x"/2 - int 1 * "e"^"2x"/2` dx

`= 1/2 "xe"^"2x" - 1/2 int "e"^"2x"` dx

`= 1/2 "x e"^"2x" - 1/2 * "e"^"2x"/2` + c

∴ I = `1/4 "e"^"2x" ("2x" - 1)` + c

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Integration - MISCELLANEOUS EXERCISE - 5 [Page 139]

APPEARS IN

Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q IV. 4) iii) | Page 139

RELATED QUESTIONS

`int (dx)/(sin^2 x cos^2 x)` equals:


Write a value of\[\int\frac{\sin x + \cos x}{\sqrt{1 + \sin 2x}} dx\]


Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Evaluate the following integrals : `int (sin2x)/(cosx)dx`


Evaluate the following integrals: `int sin 4x cos 3x dx`


Evaluate the following integrals:

`int(2)/(sqrt(x) - sqrt(x + 3)).dx`


Integrate the following functions w.r.t. x : `(1)/(2 + 3tanx)`


Integrate the following functions w.r.t. x : cos7x


Evaluate the following:

`int (1)/(25 - 9x^2)*dx`


Evaluate `int (-2)/(sqrt("5x" - 4) - sqrt("5x" - 2))`dx


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


Choose the correct alternative from the following.

`int "x"^2 (3)^("x"^3) "dx"` =


`int ("e"^(2x) + "e"^(-2x))/("e"^x)  "d"x`


`int(log(logx))/x  "d"x`


`int (1 + x)/(x + "e"^(-x))  "d"x`


`int(5x + 2)/(3x - 4) dx` = ______


`int (f^'(x))/(f(x))dx` = ______ + c.


`int x/sqrt(1 - 2x^4) dx` = ______.

(where c is a constant of integration)


Evaluate `int(1 + x + x^2/(2!))dx`


If f ′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate the following.

`int 1/ (x^2 + 4x - 5) dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x). 


What is integration by substitution?


For \[\sqrt{\frac{x-\alpha}{\beta-x}}\] or \[\sqrt{(x-\alpha)(\beta-x)}\], where \[\beta>\alpha\], which substitution is used?


After choosing \[u=g(x)\], what is the next step?


In \[\int\sin^3x\cos^2x\,dx\], which rewriting prepares the integrand for the substitution \[t=\cos x\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×