English

Integrate the following functions w.r.t. x : cos7x

Advertisements
Advertisements

Question

Integrate the following functions w.r.t. x : cos7x

Sum
Advertisements

Solution

Let I = `int cos^7x dx`

= `int cos^6x.cos x dx`

= `int (1 - sin^2x)^3 cos x dx`
Put, sin x = t
∴ cos x dx = dt
I = `int(1 - t^2)^3 dt`

= `int(1 - 3t^2 + 3t^4 - t^6)dt`

= `int 1dt - 3 int t^2dt + 3intt^4 dt - int t^6 dt`

= `t - 3(t^3/3) + 3(t^5/3) - t^7/(7) + c`

=  `sinx - sin^3x + (3)/(5)sin^5x - (1)/(7)sin^7x + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.2 (A) [Page 110]

APPEARS IN

RELATED QUESTIONS

Find `intsqrtx/sqrt(a^3-x^3)dx`


Integrate the functions:

`(e^(2x) -  e^(-2x))/(e^(2x) + e^(-2x))`


Integrate the functions:

sec2(7 – 4x)


\[\int\sqrt{9 - x^2}\text{ dx}\]

Write a value of

\[\int x^2 \sin x^3 \text{ dx }\]

Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Write a value of\[\int\frac{\cos x}{\sin x \log \sin x} dx\]

 


The value of \[\int\frac{1}{x + x \log x} dx\] is


`int "dx"/(9"x"^2 + 1)= ______. `


Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`


Integrate the following w.r.t. x:

`2x^3 - 5x + 3/x + 4/x^5`


Evaluate the following integrals:

`int x/(x + 2).dx`


Evaluate the following integrals: `int (2x - 7)/sqrt(4x - 1).dx`


Evaluate the following integrals:

`int (sin4x)/(cos2x).dx`


Integrate the following functions w.r.t. x : `(logx)^n/x`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t.x:

`(5 - 3x)(2 - 3x)^(-1/2)`


Integrate the following functions w.r.t. x : `sin(x - a)/cos(x  + b)`


Integrate the following functions w.r.t. x : `(sinx + 2cosx)/(3sinx + 4cosx)`


Evaluate the following:

`int (1)/(25 - 9x^2)*dx`


Evaluate the following : `int (1)/(4 + 3cos^2x).dx`


Choose the correct options from the given alternatives :

`int sqrt(cotx)/(sinx*cosx)*dx` =


Evaluate `int (-2)/(sqrt("5x" - 4) - sqrt("5x" - 2))`dx


Evaluate `int (3"x"^2 - 5)^2` dx


Evaluate the following.

`int x/(4x^4 - 20x^2 - 3) dx`


Evaluate the following.

`int 1/(sqrt("x"^2 -8"x" - 20))` dx


If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + ______


Evaluate: `int 1/(2"x" + 3"x" log"x")` dx


`int (log x)/(log ex)^2` dx = _________


`int (x^2 + 1)/(x^4 - x^2 + 1)`dx = ?


`int (cos x)/(1 - sin x) "dx" =` ______.


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


If f'(x) = `x + 1/x`, then f(x) is ______.


If `int(cosx - sinx)/sqrt(8 - sin2x)dx = asin^-1((sinx + cosx)/b) + c`. where c is a constant of integration, then the ordered pair (a, b) is equal to ______.


`int (x + sinx)/(1 + cosx)dx` is equal to ______.


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


`int secx/(secx - tanx)dx` equals ______.


Evaluate `int(1 + x + x^2/(2!) )dx`


Evaluate the following

`int1/(x^2 +4x-5)dx`


`int dx/((x+2)(x^2 + 1))`    ...(given)

`1/(x^2 +1) dx = tan ^-1 + c`


Evaluate the following.

`intx sqrt(1 +x^2)  dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate the following:

`int x^3/(sqrt(1+x^4))dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate the following.

`int1/(x^2+4x-5)dx`


Evaluate the following.

`int1/(x^2+4x-5)dx`


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×