मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Evaluate: ∫x⋅e2x dx

Advertisements
Advertisements

प्रश्न

Evaluate: `int "x" * "e"^"2x"` dx

बेरीज
Advertisements

उत्तर

Let I = `int "x" * "e"^"2x"` dx

`= "x" int "e"^"2x" "dx" - int["d"/"dx" ("x") int "e"^"2x" * "dx"]` dx

`= "x" * "e"^"2x"/2 - int 1 * "e"^"2x"/2` dx

`= 1/2 "xe"^"2x" - 1/2 int "e"^"2x"` dx

`= 1/2 "x e"^"2x" - 1/2 * "e"^"2x"/2` + c

∴ I = `1/4 "e"^"2x" ("2x" - 1)` + c

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Integration - MISCELLANEOUS EXERCISE - 5 [पृष्ठ १३९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q IV. 4) iii) | पृष्ठ १३९

संबंधित प्रश्‍न

Integrate the functions:

`xsqrt(x + 2)`


Integrate the functions:

`e^(2x+3)`


Integrate the functions:

`(e^(2x) - 1)/(e^(2x) + 1)`


Integrate the functions:

`sin x/(1+ cos x)`


Write a value of

\[\int e^x \left( \sin x + \cos x \right) \text{ dx}\]

 


Write a value of\[\int\frac{1}{1 + 2 e^x} \text{ dx }\].


Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


Find : ` int  (sin 2x ) /((sin^2 x + 1) ( sin^2 x + 3 ) ) dx`


Evaluate the following integrals:

`int (cos2x)/sin^2x dx` 


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


If `f'(x) = x - (3)/x^3, f(1) = (11)/(2)`, find f(x)


Integrate the following functions w.r.t. x : `(7 + 4 + 5x^2)/(2x + 3)^(3/2)`


Integrate the following functions w.r.t. x : `(1)/(x.logx.log(logx)`.


Integrate the following functions w.r.t. x : `(1)/(2 + 3tanx)`


Integrate the following functions w.r.t. x : tan5x


Evaluate the following integrals : `int sqrt((x - 7)/(x - 9)).dx`


Evaluate the following : `int (logx)2.dx`


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int 1/("a"^2 - "b"^2 "x"^2)` dx


Evaluate: ∫ |x| dx if x < 0


If f(x) = 3x + 6, g(x) = 4x + k and fog (x) = gof (x) then k = ______.


If `tan^-1x = 2tan^-1((1 - x)/(1 + x))`, then the value of x is ______ 


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


`int (cos x)/(1 - sin x) "dx" =` ______.


`int (x + sinx)/(1 + cosx)dx` is equal to ______.


Evaluate `int (1)/(x(x - 1))dx`


Evaluate the following:

`int x^3/(sqrt(1+x^4))dx`


Evaluate `int(1 + x + x^2 / (2!))dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×