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Write a Value of ∫ 1 + Log X 3 + X Log X D X

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प्रश्न

Write a value of

\[\int\frac{1 + \log x}{3 + x \log x} \text{ dx }\] .
योग
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उत्तर

\[\text{ Let I } = \int \left( \frac{1 + \log x}{3 + x \log x} \right)dx\]
\[\text{ Let 3 }+ x \log x = t\]
\[ \Rightarrow 0 + \left( x . \frac{1}{x} + \log x \right)dx = dt\]
\[ \Rightarrow \left( 1 + \log x \right)dx = dt\]
\[ \therefore I = \int \frac{dt}{t}\]
\[ = \text{ log t + C }\]
\[ = \text{ log }\left( 3 + x \log x \right) + C \left( \because t = 3 + x \log x \right)\]

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अध्याय 18: Indefinite Integrals - Very Short Answers [पृष्ठ १९७]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 18 Indefinite Integrals
Very Short Answers | Q 27 | पृष्ठ १९७

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