Advertisements
Advertisements
प्रश्न
Evaluate : `∫1/(3+2sinx+cosx)dx`
Advertisements
उत्तर
let I=`∫1/(3+2sinx+cosx)dx`
put `tan(x/2)=t`
`x=2tan^-1t`
`dx=(2dt)/(1+t^2)` and `sinx=2t/(1+t^2), cosx((1-t^2)/(1+t^2))`

`therefore I=tan^-1[tan(x/2)+1]+c`
APPEARS IN
संबंधित प्रश्न
Integrate the functions:
`1/(x-sqrtx)`
Integrate the functions:
`(2cosx - 3sinx)/(6cos x + 4 sin x)`
`(10x^9 + 10^x log_e 10)/(x^10 + 10^x) dx` equals:
Solve:
dy/dx = cos(x + y)
Evaluate: `int (2y^2)/(y^2 + 4)dx`
Write a value of\[\int\frac{\left( \tan^{- 1} x \right)^3}{1 + x^2} dx\]
Find : ` int (sin 2x ) /((sin^2 x + 1) ( sin^2 x + 3 ) ) dx`
Evaluate the following integrals : `int sinx/(1 + sinx)dx`
Evaluate the following integrals:
`int(2)/(sqrt(x) - sqrt(x + 3)).dx`
Integrate the following functions w.r.t. x : `((sin^-1 x)^(3/2))/(sqrt(1 - x^2)`
Integrate the following functions w.r.t. x : `(1)/(sqrt(x) + sqrt(x^3)`
Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`
Integrate the following functions w.r.t. x:
`(1)/(sinx.cosx + 2cos^2x)`
Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`
Integrate the following functions w.r.t. x : tan5x
Evaluate the following integrals:
`int (2x + 1)/(x^2 + 4x - 5).dx`
Evaluate the following integrals : `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`
Evaluate the following integrals:
`int (7x + 3)/sqrt(3 + 2x - x^2).dx`
Evaluate the following.
`int 1/("x"^2 + 4"x" - 5)` dx
`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?
Evaluate: `int "e"^"x" (1 + "x")/(2 + "x")^2` dx
Evaluate: `int log ("x"^2 + "x")` dx
`int "e"^x[((x + 3))/((x + 4)^2)] "d"x`
`int x^x (1 + logx) "d"x`
`int ("d"x)/(x(x^4 + 1))` = ______.
If f ′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)
`int dx/((x+2)(x^2 + 1))` ...(given)
`1/(x^2 +1) dx = tan ^-1 + c`
`int x^2/sqrt(1 - x^6)dx` = ______.
`int 1/(sin^2x cos^2x)dx` = ______.
Evaluate the following.
`int x^3/sqrt(1+x^4) dx`
Evaluate the following
`int x^3 e^(x^2) ` dx
Evaluate.
`int (5x^2 -6x + 3)/(2x -3)dx`
Evaluate `int (5x^2 - 6x + 3)/(2x - 3) dx`
Which substitution is appropriate for \[\sqrt{\frac{\mathrm{a}-x}{\mathrm{a}+x}}\] or \[\sqrt{\frac{\mathrm{a}+x}{\mathrm{a}-x}}\]?
After choosing \[u=g(x)\], what is the next step?
Which expression results after simplifying \[\int\frac{\sin(t-a)}{\sin t}\,dt\]?
