मराठी

Integrate the functions: sin (ax + b) cos (ax + b)

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प्रश्न

Integrate the functions:

sin (ax + b) cos (ax + b)

बेरीज
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उत्तर

Let `I = int sin (ax + b) cos (ax + b) dx`

Put sin (ax + b) = t

⇒ a cos (ax + b) dx = dt

∴ `I = 1/a int t  dt = 1/a * t^2/2 + C`

`= 1/(2a) t^2 + C`

`= 1/ (2a) sin^2 (ax + b) + C`

Or, put cos (ax + b) = t

⇒ -a sin (ax + b) dx = dt

∴ `I = (-1)/a int dt = (-1)/a t^2/2 + C`

`= (-cos^2 (ax + b))/(2a) + C`

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पाठ 7: Integrals - Exercise 7.2 [पृष्ठ ३०४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.2 | Q 5 | पृष्ठ ३०४

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