मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate the following integrals : ∫1+sin5x.dx - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Evaluate the following integrals : `intsqrt(1 + sin 5x).dx`

बेरीज
Advertisements

उत्तर

`intsqrt(1 + sin 5x).dx`

= `intsqrt(sin^2  (5x)/2 + cos^2  (5x)/2 + 2sin  (5x)/2 cos  (5x)/2) dx`

=  `intsqrt((cos  (5x)/2 + sin  (5x)/2)^2) dx`

= `int(cos  (5x)/2 + sin  (5x)/2) dx`

=  `intcos  (5x)/2 dx + sin  (5x)/2 dx`

= `(sin  (5x)/2)/(5/2) - (cos  (5x)/2)/(5/2) + "c"`

∴  I = `2/5 (sin  (5x)/2-cos  (5x)/2) + "c"` 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.1 [पृष्ठ १०२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.1 | Q 3.07 | पृष्ठ १०२

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate : `int_0^pi(x)/(a^2cos^2x+b^2sin^2x)dx`


Show that:  `int1/(x^2sqrt(a^2+x^2))dx=-1/a^2(sqrt(a^2+x^2)/x)+c`


Find `int((3sintheta-2)costheta)/(5-cos^2theta-4sin theta)d theta`.


Integrate the functions:

`(sin^(-1) x)/(sqrt(1-x^2))`


Integrate the functions:

`sin x/(1+ cos x)`


Integrate the functions:

`(sin x)/(1+ cos x)^2`


Integrate the functions:

`sqrt(tanx)/(sinxcos x)`


Integrate the functions:

`(1+ log x)^2/x`


\[\int\cos x \sqrt{4 - \sin^2 x}\text{ dx}\]

\[\int\sqrt{2 x^2 + 3x + 4} \text{ dx}\]

Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

Write a value of\[\int\text{ tan x }\sec^3 x\ dx\]


Write a value of\[\int\frac{\sec^2 x}{\left( 5 + \tan x \right)^4} dx\]


Write a value of

\[\int\frac{a^x}{3 + a^x} \text{ dx}\]

Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]


The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is


Evaluate : `int ("e"^"x" (1 + "x"))/("cos"^2("x""e"^"x"))"dx"`


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Integrate the following w.r.t. x : x3 + x2 – x + 1


Integrate the following functions w.r.t. x : `(7 + 4 + 5x^2)/(2x + 3)^(3/2)`


Integrate the following functions w.r.t. x : `x^2/sqrt(9 - x^6)`


Integrate the following functions w.r.t. x : `(cos3x - cos4x)/(sin3x + sin4x)`


Integrate the following functions w.r.t. x : tan5x


Evaluate the following : `int (1)/sqrt(3x^2 - 8).dx`


Evaluate the following : `int (1)/sqrt(11 - 4x^2).dx`


Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`


Evaluate the following:

`int (1)/sqrt((x - 3)(x + 2)).dx`


Evaluate the following : `int (1)/(4 + 3cos^2x).dx`


Evaluate the following integrals:

`int (2x + 1)/(x^2 + 4x - 5).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


Evaluate the following integrals : `int sqrt((x - 7)/(x - 9)).dx`


Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int ("e"^"x" + "e"^(- "x"))^2 ("e"^"x" - "e"^(-"x"))`dx


Evaluate `int (5"x" + 1)^(4/9)` dx


Evaluate: `int "e"^sqrt"x"` dx


`int e^x/x [x (log x)^2 + 2 log x]` dx = ______________


To find the value of `int ((1 + logx))/x` dx the proper substitution is ______


State whether the following statement is True or False:

`int"e"^(4x - 7)  "d"x = ("e"^(4x - 7))/(-7) + "c"`


State whether the following statement is True or False:

`int sqrt(1 + x^2) *x  "d"x = 1/3(1 + x^2)^(3/2) + "c"`


`int1/(4 + 3cos^2x)dx` = ______ 


`int sec^6 x tan x   "d"x` = ______.


`int ("d"x)/(sinx cosx + 2cos^2x)` = ______.


`int (sin  (5x)/2)/(sin  x/2)dx` is equal to ______. (where C is a constant of integration).


The integral `int ((1 - 1/sqrt(3))(cosx - sinx))/((1 + 2/sqrt(3) sin2x))dx` is equal to ______.


`int dx/(2 + cos x)` = ______.

(where C is a constant of integration)


Evaluate the following.

`int(20 - 12"e"^"x")/(3"e"^"x" - 4) "dx"`


Evaluate the following.

`int 1/(x^2 + 4x - 5)  dx`


Evaluate the following.

`intx sqrt(1 +x^2)  dx`


Evaluate:

`int(cos 2x)/sinx dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×