Advertisements
Advertisements
प्रश्न
Evaluate `int (5"x" + 1)^(4/9)` dx
Advertisements
उत्तर
Let I = `int (5"x" + 1)^(4/9)` dx
`= (5"x" + 1)^(4/9 + 1)/((4/9 + 1) xx 5)` + c
`= (5"x" + 1)^(13/9)/(13/9 xx 5)` + c
∴ I = `9/65 (5"x" + 1)^(13/9)` + c
APPEARS IN
संबंधित प्रश्न
Evaluate : `int(x-3)sqrt(x^2+3x-18) dx`
Find `intsqrtx/sqrt(a^3-x^3)dx`
Evaluate : `∫1/(cos^4x+sin^4x)dx`
Evaluate: `int 1/(x(x-1)) dx`
Write a value of\[\int\sqrt{9 + x^2} \text{ dx }\].
The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is
Evaluate the following integrals : `int sqrt(1 + sin 2x) dx`
Integrate the following function w.r.t. x:
`(10x^9 +10^x.log10)/(10^x + x^10)`
Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`
Integrate the following functions w.r.t. x:
`(sinx cos^3x)/(1 + cos^2x)`
Evaluate the following : `int sqrt((2 + x)/(2 - x)).dx`
Integrate the following functions w.r.t. x : `int (1)/(3 - 2cos 2x).dx`
Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`
Integrate the following w.r.t.x: `(3x + 1)/sqrt(-2x^2 + x + 3)`
Evaluate the following.
`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx
Evaluate the following.
`int 1/(sqrt("x"^2 -8"x" - 20))` dx
`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?
Evaluate `int "x - 1"/sqrt("x + 4")` dx
Evaluate: `int (2"e"^"x" - 3)/(4"e"^"x" + 1)` dx
Evaluate: `int "x" * "e"^"2x"` dx
`int ("e"^(2x) + "e"^(-2x))/("e"^x) "d"x`
`int (cos2x)/(sin^2x) "d"x`
If f(x) = 3x + 6, g(x) = 4x + k and fog (x) = gof (x) then k = ______.
Evaluate `int_(logsqrt(2))^(logsqrt(3)) 1/((e^x + e^-x)(e^x - e^-x)) dx`.
If f ′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)
Evaluate the following.
`int x sqrt(1 + x^2) dx`
Evaluate `int(1+x+(x^2)/(2!))dx`
Evaluate `int (1 + "x" + "x"^2/(2!))`dx
Evaluate the following.
`int 1/ (x^2 + 4x - 5) dx`
