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प्रश्न
Integrate the functions:
`1/(x + x log x)`
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उत्तर
Let I `= int 1/(x + x log x)` dx
or I `= int 1/(x (1+ log x)` dx
Put 1 + log x = t
`1/x` dx = dt
Hence, I `= int 1/t` dt
= log t + C
= log (1 + log x) + C
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