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प्रश्न
Evaluate `int(3x^2 - 5)^2 "d"x`
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उत्तर
Let I = `int(3x^2 - 5)^2 "d"x`
= `int (9x^4 - 30x^2 + 25) "d"x`
= `9intx^4"d"x - 30int x^2"d"x + 25int"d"x`
= `9((x^5)/5) - 30((x^3)/3) + 25x + "c"`
∴ I = `9/5 x^5 - 10x^3 + 25x + "c"`
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