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Write a Value of ∫ 1 − Sin X Cos 2 X D X - Mathematics

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प्रश्न

Write a value of \[\int\frac{1 - \sin x}{\cos^2 x} \text{ dx }\]

बेरीज
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उत्तर

\[\int\left( \frac{1 - \sin x}{\cos^2 x} \right) dx\]
\[ = \int\left( \frac{1}{\cos^2 x} - \frac{\sin x}{\cos^2 x} \right)dx\]
\[ \int\left( \frac{1}{\cos^2 x} - \frac{\sin x}{\cos x} \times \frac{1}{\cos x} \right) dx\]
\[ = \int\left( \sec^2 x - \sec x \tan x \right) dx\]
\[ = \tan x - \sec x + C\]

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पाठ 19: Indefinite Integrals - Very Short Answers [पृष्ठ १९८]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Very Short Answers | Q 47 | पृष्ठ १९८

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