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प्रश्न
`int x/(x + 2) "d"x`
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उत्तर
`int x/(x + 2) "d"x = int ((x + 2) - 2)/(x + 2) "d"x`
= `int(1 - 2/(x + 2)) "d"x`
= `int 1 *"d"x - 2 int 1/(x + 2) "d"x`
= x − 2log |x + 2| + c
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