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प्रश्न
Derive the equation
S = ut+ `1/2` at2
Using a speed- time graph
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उत्तर
The area enclosed under a velocity time curve gives the distance covered by a moving body. So total distance S covered by a uniformly accelerating body is given by area of trapezium OSQP.
S = area of trapezium OSQP.
AREA of rectangle OSRP + area of triangle PRQ.
S = OP x OS + `1/2` PR xQR.
s = u x t + `1/2` x t x at
S = ut + `1/2` at2
This is known as second equation of motion.
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संबंधित प्रश्न
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform acceleration.
Draw the following graph:
Speed versus time for a non-uniform acceleration.
What can you say about the nature of motion of a body of its displacement-time graph is:
A straight line inclined to the time axis with an acute angle?
Draw velocity-time graph to show:
Acceleration
Write a sentence to explain the shape of graph.
Interpret the following graph:
Sketch the shape of the velocity-time graph for a body moving with:
Uniformly velocity
State whether true or false. If false, correct the statement.
The velocity – time graph of a particle falling freely under gravity would be a straight line parallel to the x axis.
Which of the following can determine the acceleration of a moving object.
The area of the velocity-time graph gives the displacement of the body.
The velocity-displacement graph describing the motion of a bicycle is shown in the figure.
The acceleration-displacement graph of the bicycle's motion is best described by:
