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प्रश्न
The area of the right triangle under a speed-time graph is 500 m, in a time interval of 20 s. What is the speed of the body? Is the motion uniform or non-uniform?
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उत्तर
Yes the motion is uniform and the uniform speed is given by area under speed time graph divided by time interval.
So speed = 500/20 =25 m/s.
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संबंधित प्रश्न
Study the speed-time graph of a car given alongside and answer the following questions:

(i) What type of motion is represented by OA ?
(ii) What type of motion is represented by AB ?
(iii) What type of motion is represented by BC ?
(iv) What is the acceleration of car from O to A ?
(v)What is the acceleration of car from A to B ?
(vi) What is the retardation of car from B to C ?
What type of motion is represented by the following graph ?

What type of motion is represented by the following graph ?

How will you use a speed-time graph to find whether the acceleration of the body is uniform or not?
Draw the following graph:
Speed versus time for a uniformly retarded motion.
Draw velocity-time graph to show:
Deceleration
Write a sentence to explain the shape of graph.

(i) In speed time graph uniform motion is given by a straight line parallel to x axis so figure (a) denotes the uniform motion.
(ii) In speed time graph motion with increasing speed is shown by straight line with positive slope so figure (c) denotes the motion with speed increasing.
(iii) In speed time graph motion with decreasing speed is shown by straight line with negative slope so figure (b) denotes the motion with speed decreasing.
(iv) In speed time graph motion with oscillating speed is shown by zigzag line so figure {d) denotes the motion with speed oscillating.
State whether true or false. If false, correct the statement.
The velocity – time graph of a particle falling freely under gravity would be a straight line parallel to the x axis.
The area under the v-t graph represents a physical quantity that has the unit.
An object is moving in a positive direction with positive acceleration. The velocity-time graph with constant acceleration which represents the above situation is:
