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∫ Cos − 1 ( Sin X ) D X - Mathematics

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प्रश्न

\[\int \cos^{- 1} \left( \sin x \right) dx\]
बेरीज
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उत्तर

\[\int \cos^{- 1} \left( \sin x \right)dx\]

\[ = \int \cos^{- 1} \left( \cos\left( \frac{\pi}{2} - x \right) \right)dx \left[ \therefore \sin x = \cos\left( \frac{\pi}{2} - x \right) \right]\]

\[ = \int\left( \frac{\pi}{2} - x \right)dx\]

 ` = (π  x)/ 2 - x^2 / 2 + c `

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पाठ 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.02 | Q 36 | पृष्ठ १५

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