Question

\[\int \cos^{- 1} \left( \sin x \right) dx\]

Answer 1

\[\int \cos^{- 1} \left( \sin x \right)dx\]

\[ = \int \cos^{- 1} \left( \cos\left( \frac{\pi}{2} - x \right) \right)dx \left[ \therefore \sin x = \cos\left( \frac{\pi}{2} - x \right) \right]\]

\[ = \int\left( \frac{\pi}{2} - x \right)dx\]

 ` = (π  x)/ 2 - x^2 / 2 + c `