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प्रश्न

\[\  ∫    x   \text{ e}^{x^2} dx\]
बेरीज
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उत्तर

\[\int x . e^{x^2} dx\]
\[\text{Let x}^2 = t\]
\[ \Rightarrow \text{2x dx} = dt\]
\[ \Rightarrow \text{x dx} = \frac{dt}{2}\]
\[Now, \int x . e^{x^2} dx\]
\[ = \frac{1}{2}\int e^t dt\]
\[ = \frac{1}{2} e^t + C\]
\[ = \frac{1}{2} e^{x^2} + C\]

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पाठ 19: Indefinite Integrals - Exercise 19.09 [पृष्ठ ५९]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.09 | Q 59 | पृष्ठ ५९

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