मराठी

∫ ( 2 X − 3 ) 5 + √ 3 X + 2 D X

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प्रश्न

\[\int \left( 2x - 3 \right)^5 + \sqrt{3x + 2}  \text{dx} \]
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उत्तर

\[\int\left[ \left( 2x - 3 \right)^5 + \sqrt{3x + 2} \right]dx\]
\[ = \int \left( 2x - 3 \right)^5 dx + \int \left( 3x + 2 \right)^\frac{1}{2} dx\]
\[ = \frac{\left( 2x - 3 \right)^{5 + 1}}{2\left( 5 + 1 \right)} + \frac{\left( 3x + 2 \right)^\frac{1}{2} + 1}{3\left( \frac{1}{2} + 1 \right)} + C\]
\[ = \frac{\left( 2x - 3 \right)^6}{12} + \frac{2}{9} \left( 3x + 2 \right)^\frac{3}{2} + C\]

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पाठ 18: Indefinite Integrals - Exercise 19.03 [पृष्ठ २३]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 18 Indefinite Integrals
Exercise 19.03 | Q 1 | पृष्ठ २३
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