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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A Zener of power rating 1 W is to be used as a voltage regulator. If zener has a breakdown of 5 V and it has to regulate voltage which fluctuated between 3 V and 7 V

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प्रश्न

A Zener of power rating 1 W is to be used as a voltage regulator. If zener has a breakdown of 5 V and it has to regulate voltage which fluctuated between 3 V and 7 V, what should be the value of Rs for safe operation (Figure)?

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उत्तर

According to the problem, power = 1 W

Zener breakdown voltage, Vz = 5 V

Minimum voltage, Vmin = 3 V

Maximum voltage, Vmax = 7 V

We know, P = VI

So, current `I_(Z_("max")) = P/V_Z = 1/5` = 0.2 A

For safe operation Rs will be equal to `R_S = (V_("max") - V_Z)/I_(Z_("max"))`

= `(7 - 5)/0.2`

= `2/0.2`

= 10 Ω

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पाठ 14: Semiconductor Electronics - Exercises [पृष्ठ ९३]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
पाठ 14 Semiconductor Electronics
Exercises | Q 14.30 | पृष्ठ ९३

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