Advertisements
Advertisements
प्रश्न
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
Advertisements
उत्तर
Initial velocity u = 10 m/s
Acceleration a = 5 m/s2
Time t = 5s
Let 'S' be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at2
S = (10)(5) + (1/2) (5) (5) 2
S = 50 + 62.5
S = 112.5 m
APPEARS IN
संबंधित प्रश्न
Which of the following is true for displacement?
- It cannot be zero.
- Its magnitude is greater than the distance travelled by the object.
Explain the following concept in your own words with everyday examples:
Distance
Draw displacement – time graph for the following situation:
When a body is moving with uniform velocity.
Calculate the distance and displacement in the following case:
A body is moving along a circular path of radius r. What will be the distance and displacement of the body when it completes:
Half a revolution
A 50 m long train passes over a bridge at a speed of 30 km/h. If it takes 36 seconds to cross the bridge, calculate the length of the bridge.
Assertion: Displacement of a body may be zero when distance travelled by it is not zero.
Reason: The displacement is the shortest distance between initial and final position.
A body moves is a circle of radius ‘2R’ what is the distance covered and displacement of the body after 2 complete rounds?
A scalar quantity has ______.
Choose the correct option.
