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प्रश्न
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
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उत्तर
Initial velocity u = 10 m/s
Acceleration a = 5 m/s2
Time t = 5s
Let 'S' be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at2
S = (10)(5) + (1/2) (5) (5) 2
S = 50 + 62.5
S = 112.5 m
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संबंधित प्रश्न
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