Advertisements
Advertisements
प्रश्न
A body starts from rest with uniform acceleration 2 m s-2. Find the distance covered by the body in 2 s.
Advertisements
उत्तर
Initial velocity u = 0
Acceleration a = 2 m/s2
Time t = 2 s
Let 'S' be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at2
S = 0 + (1/2) (2) (2) 2
S = 4 m
APPEARS IN
संबंधित प्रश्न
A body travels a distance of 3 km towards East, then 4 km towards North and finally 9 km towards East.
What is the total distance travelled ?
What information about the motion of a body are obtained from the displacement-time graph?
Define Displacement.
Can you suggest the kind of motion of a body from the following distance – time graph?
Can you suggest the kind of motion of a body from the following distance – time graph?
Calculate the distance and displacement in the following case:
The table below shows the distance travelled by two vehicles A and B during each second:
| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Distance travelled by A (m) | 0 | 20 | 80 | 180 | 240 | 300 | 360 | 420 |
| Distance travelled by B (m) | 0 | 10 | 40 | 90 | 160 | 250 | 360 | 490 |
Which vehicle is moving with a constant acceleration?
Distance travelled by a body in a given time ______.
A body moves is a circle of radius ‘2R’ what is the distance covered and displacement of the body after 2 complete rounds?
Assertion: If the displacement of the body is zero, the distance covered by it may not be zero.
Reason: Displacement is a vector & distance is a scalar quantity.
