Advertisements
Advertisements
Question
A body starts from rest with uniform acceleration 2 m s-2. Find the distance covered by the body in 2 s.
Advertisements
Solution
Initial velocity u = 0
Acceleration a = 2 m/s2
Time t = 2 s
Let 'S' be the distance covered.
Using the second equation of motion,
S = ut + (1/2) at2
S = 0 + (1/2) (2) (2) 2
S = 4 m
APPEARS IN
RELATED QUESTIONS
Define displacement. State its unit.
Define Distance.
Can you suggest the kind of motion of a body from the following distance – time graph?
A motorbike running at 90 kmh−1, is slowed down to 54 kmh−1 by the application of brakes, over a distance of 40 m. If the brakes are applied with the same force, calculate
- total time in which bike comes to rest
- total distance travelled by bike.
Is distance covered during nth second more than the distance covered in n seconds?
The graph shows how the velocity of a scooter varies with time in 50 s.
Work out: The distance traveled in 10 s, 20 s, and 50 s.
A 50 m long train passes over a bridge at a speed of 30 km/h. If it takes 36 seconds to cross the bridge, calculate the length of the bridge.
State whether true or false. If false, correct the statement.
Distance covered by a particle never becomes zero but displacement becomes zero.
Write a note on the following:
Nautical mile
A particle is moving in a circular pattern of radius r. The displacement after half a circle would be ______.
