Statement
When a conducting rod moves in a uniform magnetic field, the charges in it experience a magnetic force (Lorentz force) and a potential difference (motional emf) is produced across its ends. The induced potential difference (motional emf) is given by
V = Bvlwhen a straight conductor of length l moves with velocity u perpendicular to a magnetic field B.
Explanation / Proof
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A conducting rod JK of length l is placed in a uniform magnetic field B (perpendicular to the plane) and moved with constant velocity v perpendicular to its axis.
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A charge qqq moving with velocity v in magnetic field B experiences a magnetic force of magnitude
Fm = qvB
This force is called the Lorentz force and acts perpendicular to both B and v.
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Due to this force, electrons move toward end K, making J positive and K negative, so a potential difference V is produced and an electric field E is set up in the rod with magnitude
E = \[\frac {V}{l}\] ...(i)
The electric field exerts an electric force on charge qqq of magnitude
Fe = qE
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Electrons keep moving until the electric force balances the magnetic force:
Fe = Fm ⇒ qE = qvB ⇒ E = Bv...(ii)
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Comparing (i) and (ii):
\[\frac{V}{l}=Bv\Rightarrow V=Bvl\]
Conclusion
The induced potential difference across the ends of a straight conductor moving with velocity v perpendicular to a magnetic field B is
V = BvlThis induced potential difference is called motional emf.
