Definitions [20]
For any three given vectors, the scalar product of one of the vectors and the cross product of the remaining two, is called a scalar triple product
Thus, \[\vec{a},\vec{b},\vec{c}\] are three vectors, then \[(\vec{a}\times\vec{b})\cdot\vec{c}\]is called the scalar triple product and is denoted by \[[\vec{a}\vec{b}\vec{c}]\mathrm{~or~}[a,b,c]\]
When the direction of rotation is anticlockwise, then the rotation will move the screw upwards. It is called a right-handed orientation or a right-handed screw rule.
A scalar quantity is a physical quantity that has magnitude only.
A vector quantity is a physical quantity that has magnitude as well as direction.
A vector is a quantity that has magnitude as well as direction. Geometrically, a vector is represented by a directed line segment such as \[\vec{AB}\], where A is the initial point and B is the terminal point.
The magnitude of vector \[\vec{AB}\] is the length of the directed line segment AB. It is written as \[|\vec{AB}|\], \[|\vec{a}|\], or simply a. The magnitude of a vector is never negative because it represents length.
In three-dimensional geometry, the vector drawn from the origin O(0, 0, 0) to a point P(x, y, z) is called the position vector of the point P. It is written as \[\vec{OP}\]. If point P(x, y, z) is given, then the magnitude of its position vector is:
In general, if a₁, a₂, …, aₙ are n vectors and t₁, t₂, …, tₙ are n scalars, then linear combination of vectors a₁, a₂, …, aₙ is t₁a₁ + t₂a₂ + … + tₙaₙ.
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For 2 vectors:
\[\overline{\mathbf{r}}=x\overline{\mathbf{a}}+y\overline{\mathbf{b}}\] -
For 3 vectors:
\[\mathbf{\overline{r}}=x\mathbf{\overline{a}}+y\mathbf{\overline{b}}+\mathbf{z}\mathbf{\overline{c}}\]
Two vectors a and b are collinear if there exists a scalar λ such that a = λb.
Three points A(a), B(b) and C(c) are collinear iff ∃ non-zero scalars x, y, z such that xa + yb + zc = 0, where x + y + z = 0.
Three points A(a), B(b) and C(c) are collinear if AB × BC = 0 i.e. a × b + b × c + c × a = 0.
a and b are two non-collinear vectors. A vector r is coplanar with a and b if and only if there exists a unique scalar λ₁ and λ₂ such that r = λ₁a + λ₂b
Three vectors a₁i + a₂j + a₃k, b₁i + b₂j + b₃k and c₁i + c₂j + c₃k are coplanar, if \[\begin{vmatrix} a_{1} & a_{2} & a_{3} \\ b_{1} & b_{2} & b_{3} \\ c_{1} & c_{2} & c_{3} \end{vmatrix}=0.\]
Four points with position vectors a = a₁i + a₂j + a₃k, b = b₁i + b₂j + b₃k, c = c₁i + c₂j + c₃k and d = d₁i + d₂j + d₃k will be coplanar iff
\[\begin{vmatrix} a_1 & a_2 & a_3 & 1 \\ b_1 & b_2 & b_3 & 1 \\ c_1 & c_2 & c_3 & 1 \\ d_1 & d_2 & d_3 & 1 \end{vmatrix}=0.\]
If P(x, y, z) is a point, then its position vector is
This is called the component form of a vector.
If \[P_1(x_1, y_1, z_1)\] and \[P_2(x_2, y_2, z_2)\] are two points in space, then the vector joining \[P_1\] to \[P_2\] is the vector
\[\vec{P_1P_2}\]
representing the displacement from \[P_1\] (initial point) to \[P_2\] (terminal point).
Magnitude of vector:
If \[\vec{a}\] and \[\vec{b}\] are two vectors with angle \[\theta\] between them, then their vector product is:
where \[\hat{n}\] is a unit vector perpendicular to both \[\vec{a}\] and \[\vec{b}\], in the direction given by the right-hand rule.
Cross Product Angle: \[\sin \theta = \frac{|\vec{a} \times \vec{b}|}{|\vec{a}| |\vec{b}|}\]
Projection is the part of one vector in the direction of another vector.
Scalar projection of \[\vec{a}\] on \[\vec{b}\]
Vector projection of \[\vec{a}\] on \[\vec{b}\]
If \[\vec{a}\] and \[\vec{b}\] are two vectors and \[\theta\] is the angle between them, then their scalar product is given by:
The angles made by a vector with the positive directions of the X-axis, Y-axis and Z-axis are called direction angles of the vector, denoted by α, β, and γ.
If α, β and γ are the direction angles of a vector, then the cosines of these angles, i.e.
l = cosα, m = cosβ, n = cosγ
are called the direction cosines of the vector.
If point is (x,y,z) and distance r: \[\cos\alpha=\frac{x}{r},\quad\cos\beta=\frac{y}{r},\quad\cos\gamma=\frac{z}{r}\]
If l, m, n are direction cosines of a line and if a, b, c are real numbers such that \[\frac{\mathrm{a}}{l}=\frac{\mathrm{b}}{\mathrm{m}}=\frac{\mathrm{c}}{\mathrm{n}}=\lambda,\] then a, b, c are called direction ratios of that line.
The scalar triple product of three vectors a, b, and c is defined as
(a × b) · c = |a| |b| |c| sinθ cosφ,
where θ is the angle between a and b, and φ is the angle between a × b and c. It is also defined as [a b c].
For vectors \[\overline{a}\], \[\overline{b}\] and \[\overline{c}\] in the space, we define the vector triple product as
\[\overset{-}{\operatorname*{\operatorname*{a}}}\times\left(\overset{-}{\operatorname*{\operatorname*{b}}}\times\overset{-}{\operatorname*{\operatorname*{c}}}\right)=\left(\overset{-}{\operatorname*{\operatorname*{a}}}\cdot\overset{-}{\operatorname*{\operatorname*{c}}}\right)\overline{b}-\left(\overset{-}{\operatorname*{\operatorname*{a}}}\cdot\overline{b}\right)\overline{c}\]
Formulae [6]
Magnitude of Vector: \[\mid r\mid=\sqrt{x^{2}+y^{2}}\]
\[\theta=\tan^{-1}\left(\frac{y}{x}\right)\]
If R (r̄) is the mid-point of the line segment joining the points A (ā) and B (b̄), then
\[\overline{\mathbf{r}}=\frac{\overline{\mathbf{a}}+\overline{\mathbf{b}}}{2}\]
Centroid of Triangle:
\[\mathbf{\overline{g}}=\frac{\mathbf{\overline{a}}+\mathbf{\overline{b}}+\mathbf{\overline{c}}}{3}\]
Centroid of Tetrahedron:
\[\overline{\mathbf{g}}=\frac{\overline{\mathbf{a}}+\overline{\mathbf{b}}+\overline{\mathbf{c}}+\overline{\mathbf{d}}}{4}\]
Incentre of Triangle:
\[\overline{\mathrm{h}}=\frac{\left|\overline{\mathrm{AB}}\right|\overline{\mathrm{c}}+\left|\overline{\mathrm{BC}}\right|\overline{\mathrm{a}}+\left|\overline{\mathrm{AC}}\right|\overline{\mathrm{b}}}{\left|\overline{\mathrm{AB}}\right|+\left|\overline{\mathrm{BC}}\right|+\left|\overline{\mathrm{AC}}\right|}\]
Orthocentre of Triangle:
\[\overline{\mathrm{p}}=\frac{\tan A\left(\overline{\mathrm{a}}\right)+\tan B\left(\overline{\mathrm{b}}\right)+\tan C\left(\overline{\mathrm{c}}\right)}{\tan A+\tan B+\tan C}\]
\[\mathbf{\overline{r}}=\mathbf{\frac{m\overline{b}+n\overline{a}}{m+n}}\]

\[\overline{\mathrm{r}}=\frac{\mathrm{m\overline{b}-n\overline{a}}}{\mathrm{m-n}}\]

Parallelepiped: Volume = [a b c]
Tetrahedron: \[\frac{1}{6}\] [a b c]
Theorems and Laws [5]
If two vectors are represented by two sides of a triangle taken in order, then their sum is represented by the third side of the triangle taken in the same order.

If two vectors are represented by two adjacent sides of a parallelogram, then their resultant is represented by the diagonal passing through their common initial point.

The difference of two vectors is obtained by adding the negative of one vector.
Using properties of scalar triple product, prove that `[(bara + barb, barb + barc, barc + bara)] = 2[(bara, barb, barc)]`.
L.H.S = `[(bara + barb, barb + barc, barc + bara)]`
= `(bara + barb) . [(barb + barc) xx (barc + bara)]`
= `(bara + barb) . [barb xx barc + barb xx bara + barc xx barc + barc xx bara]`
= `(bara + barb) . [barb xx barc + barb xx bara + barc xx bara] ...[∵ barc xx barc = bar0]`
= `bara . [(barb xx barc) + (barb xx bara) + (barc xx bara)] + barb . [(barb xx barc) + (barb xx bara) + (barc xx bara)]`
= `bara . (barb xx barc) + bara . (barb xx bara) + bara . (barc xx bara) + barb . (barb xx barc) + barb(barb xx bara) + barb(barc xx bara)`
= `[bara barb barc] + [bara barb bara] + [bara barc bara] + [barb barb barc] + [barb barb bara] + [barb barc bara]`
= `[bara barb barc] + 0 + 0 + 0 + 0 + [bara barb barc]`
= `2[bara barb barc]`
= R.H.S
Prove by vector method, that the angle subtended on semicircle is a right angle.
Let seg AB be a diameter of a circle with centre C and P be any point on the circle other than A and B.
Then ∠APB is an angle subtended on a semicircle.
Let `bar"AC" = bar"CB" = bar"a"` and `bar"CP" = bar"r"`
Then `|bar"a"| = |bar"r"|` ....(1)

`bar"AP" = bar"AC" + bar"CP"`
= `bar"a" + bar"r"`
= `bar"r" + bar"a"`
`bar"BP" = bar"BC" + bar"CP"`
= `- bar"CB" + bar"CP"`
= `- bar"a" + bar"r"`
∴ `bar"AP".bar"BP" = (bar"r" + bar"a").(bar"r" - bar"a")`
= `bar"r".bar"r" - bar"r".bar"a" + bar"a".bar"r" - bar"a".bar"a"`
= `|bar"r"|^2 - |bar"a"|^2`
= 0 ....`(∵ bar"r".bar"a" = bar"a".bar"r")`
∴ `bar"AP" ⊥ bar"BP"`
∴ ∠APB is a right angle.
Hence, the angle subtended on a semicircle is the right angle.
Consider the circle with the centre at O and AB is the diameter.
Let `bar(OA) = bar a, bar(OB) = bar b, bar(OC) = bar c`

∴ `|bar a| =|bar b| = |bar c| = r` ...(1)
and `bar a = -bar b` ...(2)
Consider:
`bar (AC) * bar (BC) = (bar c - bar a) * (bar c - bar b)`
= `(bar c - bar a) * (bar c + bar a)` ...[From (2)]
= `|bar c|^2 - |bar a|^2`
= r2 − r2 ...[From (1)]
= 0
∴ `bar(AC) * bar(BC) = 0`
∴ `bar(AC)` is perpendicular to `bar(BC)`
∴ ∠ACB = 90°
∴ Angle subtended on semi-circle is a right angle.
Key Points
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Position of dot & cross doesn’t matter
\[(\vec{a}\times\vec{b})\cdot\vec{c}=\vec{a}\cdot(\vec{b}\times\vec{c})\] -
Cyclic order unchanged ⇒ STP unchanged
\[[\vec{a}\operatorname{\vec{b}}\vec{c}]=[\vec{b}\operatorname{\vec{c}}\vec{a}]=[\vec{c}\operatorname{\vec{a}}\vec{b}]\] -
Interchanging two vectors changes the sign
\[[\vec{a}\operatorname{\vec{b}}\vec{c}]=-\left[\vec{b}\operatorname{\vec{a}}\vec{c}\right]\] - If any two vectors are equal
\[[\vec{a}\operatorname{\vec{a}}\vec{b}]=0\]
- If any two vectors are parallel
\[[\vec{a}\operatorname{\vec{b}}\operatorname{\vec{c}}]=0\]
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Scalars have only magnitude.
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Vectors have magnitude and direction.
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Vectors are represented by directed line segments.
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\[\vec{AB}\] represents a vector from A to B.
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Magnitude of a vector is its length and is always non-negative.
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\[\vec{OP}\] is the position vector of point \[P(x, y, z)\].
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\[|\vec{OP}| = \sqrt{x^2 + y^2 + z^2}\].
| Type of Vector | Definition | Main Property | Simple Recall Cue |
|---|---|---|---|
| Zero vector | Initial and terminal points are same | Magnitude = 0 | No displacement |
| Unit vector | Magnitude is 1 | Gives direction conveniently | Length 1 |
| Coinitial vectors | Same starting point | Start together | Common origin |
| Collinear vectors | Parallel to same line | Lie along one line | Same line |
| Equal vectors | Same magnitude and direction | Position may differ | Same length + same direction |
| Negative vectors | Same magnitude, opposite direction | Sign changes direction | Reverse arrow |
| Free vectors | Can shift parallelly without change | Independent of position | Slide without changing |
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A vector has both magnitude and direction.
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Resultant means the combined effect of two or more vectors.
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Triangle law uses head-to-tail arrangement.
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Parallelogram law uses adjacent sides from the same initial point.
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Vector addition is commutative and associative.
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Zero vector is the identity element for vector addition.
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Difference of vectors is obtained by adding the negative of a vector.
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Initial point: starting point of vector; terminal point: ending point.
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Vector joining \[P_1(x_1, y_1, z_1)\] to \[P_2(x_2, y_2, z_2)\]:
\[\vec{P_1P_2} = (x_2 - x_1)\hat{i} + (y_2 - y_1)\hat{j} + (z_2 - z_1)\hat{k}\] -
Order matters: \[\vec{P_1P_2} = -\vec{P_2P_1}\]
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Magnitude equals distance between points:
\[|\vec{P_1P_2}| = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}\]
- Section formula gives the position vector of a point dividing a line segment in a given ratio.
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For internal division, use \(\dfrac{m\vec{b}+n\vec{a}}{m+n}\).
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For external division, use \(\dfrac{m\vec{b}-n\vec{a}}{m-n}\).
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Midpoint is the special case when the ratio is \(1:1\).
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Centroid formulas are natural extensions of the same averaging idea.
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Dot product result is a scalar.
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Cross product result is a vector.
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Dot product uses cosine; cross product uses sine.
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Dot product helps in angle and projection questions.
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Cross product helps in area and direction questions.
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\[\vec{a} \cdot \vec{b} = 0\] indicates perpendicular non-zero vectors.
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\[\vec{a} \times \vec{b} = \vec{0}\] indicates parallel vectors.
- Applications of Cross Product:
Area of Triangle:
\[\frac{1}{2}|\vec{a} \times \vec{b}|\]Area of Parallelogram:
\[|\vec{a} \times \vec{b}|\]
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Direction angles are the angles a line makes with the positive coordinate axes.
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Direction cosines are \[\cos \alpha\], \[\cos \beta\], and \[\cos \gamma\].
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If direction cosines are (l, m, n), then \[l^2 + m^2 + n^2 = 1\].
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Direction ratios are any numbers proportional to direction cosines.
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If direction ratios are (a, b, c), then corresponding direction cosines are:
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For points \[A(x_1, y_1, z_1)\], \[B(x_2, y_2, z_2)\], direction ratios of AB are \[(x_2 - x_1, y_2 - y_1, z_2 - z_1)\].
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Angle between two lines can be found using either direction cosines or direction ratios.
Important Questions [22]
- If a, b, c are the position vectors of the points A, B, C respectively and 2a+3b−5c=0, then find the ratio in which the point C divides line segment AB.
- If a,b,c Are Position Vectors of the Points A, B, C Respectively Such that 3a+ 5b-8c = 0, Find The Ratio in Which a Divides Bc.
- Find the Direction Ratios of a Vector Perpendicular to the Two Lines Whose Direction Ratios Are -2, 1, -1, and -3, -4, 1.
- If the vectors −3i+4j−2k, i+2k, i−pj are coplanar, then the value of of p is
- If the vectors 2i-qj+3k and 4i-5j+6k are collinear, then value of q is
- Show that the Points ( 7,4, 2), ( 2,1,0) a B and (3, 2,2) C Are Collinear. .
- If the vectors 2i^-3j^+4k^ and pi^+6j^-8k^ are collinear, then find the value of p.
- Find the volume of the parallelopiped whose coterminus edges are given by vectors 2i+5j-4k, 5i+7j+5k and 4i+5j-2k
- Find the Volume of the Parallelopiped, If the Coterminus Edges Are Given by the Vectors
- Find the Value of P, If the Vectors ˆ I − 2 ˆ J + ˆ K , 2 ˆ I − 5 ˆ J + P ˆ K , 5 ˆ I − 9 ˆ J + 4 ˆ K Are Coplanar.
- Prove by vector method, that the angle subtended on semicircle is a right angle.
- If the vectors -3i^+4j^-2k^,i^+2k^ and i^-pj^ are coplanar, then find the value of p.
- Using properties of scalar triple product, prove that [(bara + barb, barb + barc, barc + bara)] = 2[(bara, barb, barc)].
- Prove that the volume of a tetrahedron with coterminus edges a¯,b¯ and c¯ is 16[a¯b¯c¯].
- If A, B, C, D are (1, 1, 1), (2, 1, 3), (3, 2, 2), (3, 3, 4) respectively, then find the volume of parallelopiped with AB, AC and AD as the concurrent edges.
- Find the volume of the parallelopiped whose vertices are A (3, 2, −1), B (−2, 2, −3) C (3, 5, −2) and D (−2, 5, 4).
- Prove that the Volume of a Parallelopiped with Coterminal Edges as a,b,c Hence Find the Volume of the Parallelopiped with Coterminal Edges i+j, j+k
- If C = 3a- 2b Prove That A B C=0
- Find the volume of the parallelopiped whose coterminus edges are given by vectors 2i+3j-4k, 5i+7j+5k and 4i+5j-2k
- if a=3i-j+4k, b=2i+3j-k, c=-5i+2j+3k then a.(b x c)
- Find the Volume of a Tetrahedron Whose Vertices Are A(−1, 2, 3), B(3, −2, 1), C(2, 1, 3) and D(−1, −2, 4)
- If Bara = 3hati - 2hatj+7hatk, Barb = 5hati + Hatj -2hatk and Barc = Hati + Hatj - Hatk Then Find Bara.(Barbxxbarc)
Concepts [15]
- Overview of Vectors
- Basic Concepts of Vector Algebra
- Types of Vectors in Algebra
- Algebra of Vectors > Scalar Multiplication
- Algebra of Vectors > Addition & Subtraction of Two Vectors
- Collinearity and Coplanarity of Vectors
- Vectors in Coordinate Geometry
- Components of Vector in Algebra
- Vector Joining Two Points in Algebra
- Section Formula in Vector Algebra
- Product of Two Vectors > Scalar (Dot) Product
- Product of Two Vectors > Vector (Cross) Product
- Direction Ratios, Direction Cosine & Direction Angles in Vector
- Scalar Triple Product
- Vector Triple Product
