Advertisements
Advertisements
प्रश्न
Write an expression for the distance S covered in time t by a body which is initially at rest and starts moving with a constant acceleration a.
Advertisements
उत्तर
Distance = s, time = t, initial velocity u = 0 and acceleration = a.
Using the second equation of motion and substituting the above values we get,
s = ut + (1/2) at2
s = `1/2 "at"^2`
APPEARS IN
संबंधित प्रश्न
Is displacement a scalar quantity ?
An ant travels a distance of 8 cm from P to Q and then moves a distance of 6 cm at right angles to PQ. Find its resultant displacement.
Figure (a) shows the velocity-time graph for the motion of a body. Use it to find the displacement of the body at t = 1 s, 2 s, 3 s and 4 s, then draw on Figure (b), the displacement-time graph for it.
 |
 |
| (a) | (b) |
Can you suggest the kind of motion of a body from the following distance – time graph?
Can you suggest the kind of motion of a body from the following distance – time graph?
From the displacement – time graph shown given below calculate:
- Average velocity in the first three seconds.
- Displacement from the initial position at the end of 13 s.
- Time after which the body is at the initial position,
- Average velocity after 8 s.
An object covers a distance of S meters in t seconds as follows :
| S (meters) | 0 | 8 | 20 | 20 | 16 | 10 | 0 |
| t (Seconds) | 80 | 2 | 5 | 10 | 12 | 15 | 10 |
Plot a graph, taking t on X-axis and S on Y-axis. Determine the velocity of the object at time
(i) 6 s, and
(ii) 14 s.
A particle is moving in a circular path of radius r. The displacement after half a circle would be
The shortest distance between two places is ______.
Distinguish distance and displacement.
