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प्रश्न
Write an expression for the distance S covered in time t by a body which is initially at rest and starts moving with a constant acceleration a.
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उत्तर
Distance = s, time = t, initial velocity u = 0 and acceleration = a.
Using the second equation of motion and substituting the above values we get,
s = ut + (1/2) at2
s = `1/2 "at"^2`
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संबंधित प्रश्न
Which of the following is true for displacement?
- It cannot be zero.
- Its magnitude is greater than the distance travelled by the object.
Is displacement a scalar quantity ?
If on a round trip you travel 6 km and then arrive back home :
What distance have you travelled ?
Can you suggest the kind of motion of a body from the following distance – time graph?
From the displacement – time graph shown given below calculate :
- Velocity between 0 – 2 s.
- Velocity between 8 s – 12 s.
- Average velocity between 5 s – 12 s.
Match the following.
| 1. | Displacement | Knot |
| 2. | Light travelling through vacuum | Geometric centre |
| 3. | Speed of ship | Metre |
| 4. | Centre of gravity of geometrical shaped objects | Larger base area |
| 5. | Stability | Uniform velocity |
State whether true or false. If false, correct the statement.
Distance covered by a particle never becomes zero but displacement becomes zero.
In which of the following cases of motions, the distance moved and the magnitude of displacement are equal?
A car starts from rest and moves along the x-axis with constant acceleration 5 ms–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?
Choose the correct option.
