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Why on dilution the m Λm of CHA3COOH increases very fast, while that of CHA3COONa increases gradually?

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प्रश्न

Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?

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उत्तर

In the case of \[\ce{CH3COOH}\], which is a weak electrolyte, the number of ions increase on dilution due to an increase in degree of dissociation.

\[\ce{CH3COOH + H2O ⇌ CH3COO^{-} (aq) + H3O^{+}}\]

In the case of strong electrolyte such as \[\ce{CH3COONa}\], the number of ions remains the same but the interionic attraction decreases.

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अध्याय 3: Electrochemistry - Exercises [पृष्ठ ४०]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 3 Electrochemistry
Exercises | Q III. 49. | पृष्ठ ४०

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\[\begin{array}{cc}
\end{array}\]\[\begin{bmatrix}
\ce{\Lambda^{\circ}_{H^+} = 350 S cm^2 mol^{-1}}\\
\ce{\Lambda^{\circ}_{CH_3COO^-} = 50 S cm^2 mol^{-1}}
\end{bmatrix}\]


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