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Match the items of Column I and Column II on the basis of data given below: EF2F-Θ = 2.87 V, ELi+Li-Θ = − 3.5V, EAu3+AuΘ = 1.4 V, EBr2Br-Θ = 1.09 V Column I Column II (i) F2 (a) metal is the stronges - Chemistry

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प्रश्न

Match the items of Column I and Column II on the basis of data given below:

`E_("F"_2//"F"^-)^Θ` = 2.87 V, `"E"_(("Li"^(+))//("Li"^-))^Θ` = − 3.5V, `"E"_(("Au"^(3+))//("Au"))^Θ` = 1.4 V, `"E"_(("Br"_(2))//("Br"^-))^Θ` = 1.09 V

Column I Column II
(i) F2 (a) metal is the strongest reducing agent
(ii) Li (b) metal ion which is the weakest oxidising agent
(iii) Au3+ (c) non metal which is the best oxidising agent
(iv) Br (d) unreactive metal
(v) Au (e) anion that can be oxidised by Au3+
(vi) Li+ (f) anion which is the weakest reducing agent
(vii) F (g) metal ion which is an oxidising agent
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उत्तर

Column I Column II
(i) F2 (c) non metal which is the best oxidising agent
(ii) Li (a) metal is the strongest reducing agent
(iii) Au3+ (g) metal ion which is an oxidising agent
(iv) Br (e) anion that can be oxidised by Au3+
(v) Au (d) unreactive metal
(vi) Li+ (b) metal ion which is the weakest oxidising agent
(vii) F (f) anion which is the weakest reducing agent
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अध्याय 3: Electrochemistry - Exercises [पृष्ठ ४१]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 3 Electrochemistry
Exercises | Q IV. 55. | पृष्ठ ४१

संबंधित प्रश्न

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.


State Kohlrausch Law.


Why conductivity of an electrolyte solution decreases with the decrease in concentration ?


Define the following terms: Molar conductivity (m)


 How can you determine limiting molar conductivity,   0 m for strong electrolyte and weak electrolyte?


Molar conductivity denoted by the symbol Λm is related to the conductivity of the solution by the equation (k is the conductivity and c is the concentration).


Kohlrausch law of independent migration of ions states ____________.


Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.


When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.


Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?


The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol–1 respectively. The limiting molar conductivity Λ° for NaBr is ______.


Which of the following halogen acids is the strongest reducing agent?


The variation of molar conductivity with concentration of an electrolyte (X) m aqueous solution is shown in the given figure.

The electrolyte X is ______.


Assertion (A) : Conductivity decreases with decrease in concentration of electrolyte.

Reason (R) : Number of ions per unit volume that carry the current in a solution decreases on dilution.


Assertion (A): Molar conductivity decreases with increase in concentration.

Reason (R): When concentration approaches zero, the molar conductivity is known as limiting molar conductivity.


The specific conductance of 2.5 × 10-4 M formic acid is 5.25 × 10-5 ohm-1 cm-1. Calculate its molar conductivity and degree of dissociation.

Given `λ°_("H"^+)` = 349.5 ohm-1 cm2 mol-1 and

`λ°_("HCOO"^-)  = 50.5 " ohm"^-1 "cm"^2  "mol"^-1`


The resistance of a conductivity cell with a 0.1 M KCl solution is 200 ohm. When the same cell is filled with a 0.02 M NaCl solution, the resistance is 1100 ohm. If the conductivity of 0.1 M KCl solution is 0.0129 ohm-1 cm-1, calculate the cell constant and molar conductivity of 0.02 M NaCl solution.


The solution of two electrolytes A and B are diluted. ^m of B increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Give a reason.


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