Advertisements
Advertisements
प्रश्न
The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.
Advertisements
उत्तर
κ (S cm−1) = 0.025 S cm−1 and molarity (mol L−1) = 0.20 M
`Molar conductivity (A_m)=K/(1000xxmolarity)=0.025/(1000xx0.20)=1.25xx10^(-4)Scm^2mol^(-1)`
APPEARS IN
संबंधित प्रश्न
Define “Molar conductivity”.
Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given: Conductivity of 0.1 M KCl solution is 1.29 S m-1 .]
Write mathematical expression of molar conductivity of the given solution at infinite dilution.
The S.I. unit of cell constant for conductivity cell is __________.
Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.
When acidulated water (dil.H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.
Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?
Which of the following solutions of KCl will have the highest value of molar conductivity?
Conductivity of 2 × 10−3 M methanoic acid is 8 × 10−5 S cm−1. Calculate its molar conductivity and degree of dissociation if `∧_"m"^0` for methanoic acid, is 404 S cm2 mol−3.
Suggest a way to determine the `∧_"m"^∘`value of water.
