Advertisements
Advertisements
प्रश्न
Conductivity of 2 × 10−3 M methanoic acid is 8 × 10−5 S cm−1. Calculate its molar conductivity and degree of dissociation if `∧_"m"^0` for methanoic acid, is 404 S cm2 mol−3.
Advertisements
उत्तर
Given: Conductivity (K) = 8 × 10−5 S cm−1
Molarity (M) = 2 × 10−3 M
Formula:
Molar conductivity, `∧_"m"^"c" = ("K" xx 1000)/"C"`
Degree of dissociation, α = `∧_"m"^"c"/∧_"m"^0`
`∧_"m"^0 = ("K" xx 1000)/"C"` S cm2 mol−1
= `(8 xx 10^-5 xx 1000)/(2 xx 10^-3)`
= 40 S cm2 mol−1
`∝` = `(∧_"m"^"c")/(∧_"m"^0)`
= `40/404`
= 0.1
APPEARS IN
संबंधित प्रश्न
State Kohlrausch’s law of independent migration of ions.
Define limiting molar conductivity.
Write mathematical expression of molar conductivity of the given solution at infinite dilution.
How can you determine limiting molar conductivity, 0 m for strong electrolyte and weak electrolyte?
Which of the statements about solutions of electrolytes is not correct?
Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.
Why on dilution the m Λm of \[\ce{CH3COOH}\] increases very fast, while that of \[\ce{CH3COONa}\] increases gradually?
The limiting molar conductivities Λ° for NaCl, KBr and KCl are 126, 152 and 150 S cm2 mol–1 respectively. The limiting molar conductivity Λ° for NaBr is ______.
Molar conductivity of substance “A” is 5.9 × 103 S/m and “B” is 1 × 10–16 S/m. Which of the two is most likely to be copper metal and why?
The unit of molar conductivity is ______.
