Advertisements
Advertisements
प्रश्न
Which of the following reagents can be used to oxidise primary alcohols to aldehydes?
(i) \[\ce{CrO3}\] in anhydrous medium.
(ii) \[\ce{KMnO4}\] in acidic medium.
(iii) Pyridinium chlorochromate.
(iv) Heat in the presence of Cu at 573 K.
Advertisements
उत्तर
(i) \[\ce{CrO3}\] in anhydrous medium.
(iii) Pyridinium chlorochromate.
(iv) Heat in the presence of Cu at 573 K.
Explanation:
Strong oxidising agents such as acidified potassium permanganate are used for getting carboxylic acids from alcohols directly. \[\ce{CrO3}\] in anhydrous medium is used as the oxidising agent for the isolation of aldehydes.
\[\ce{RCH2OH ->[CrO3] RCHO}\]
A better reagent for the oxidation of primary alcohols to aldehydes in good yield is pyridinium chlorochromate (PCC), a complex for chromium trioxide with pyridine and HCl.
APPEARS IN
संबंधित प्रश्न
Name the following compound according to IUPAC system.

Name the following compound according to IUPAC system.
\[\begin{array}{cc}
\ce{CH3 - C = C - CH2OH}\\
\phantom{}|\phantom{....}|\phantom{....}\\
\phantom{}\ce{CH3}\phantom{.}\ce{Br}\phantom{...}
\end{array}\]
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{..........}|\\
\phantom{............}\ce{CH3}
\end{array}\]
Write IUPAC name of the following compound:
C6H5 – O – C2H5
Write structural formulae for Cyclohex-2-en-1-ol.
Write IUPAC name of the following
\[\begin{array}{cc}\ce{CH3-CH-CH-CH2-OH}\\|\phantom{.....}|\phantom{.......}\\\ce{OH}\phantom{..}\ce{CH3}\phantom{.....}\end{array}\]
Isopropyl alcohol on oxidation forms:
n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?
Ethylene reacts with Baeyer’s reagent to give ______.
\[\ce{HC ≡ CH ->[HgSO4][H2SO4] ->[CH3MgBr][H2O] ->[PBr3]}\]
\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]
The product ‘Z’ is:
IUPAC name of the compound is:
\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
The correct acidic strength order of the following is:

(I)

(II)

(III)
What happens when benzene diazonium chloride is heated with water?
Arrange the following compounds in decreasing order of acidity.
\[\ce{H2O, ROH, HC ≡ CH}\]
Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.
| Column I | Column II | ||
| (i) | CH3—O—CH3 | (a) | ![]() |
| (ii) | \[\begin{array}{cc} \ce{CH3}\phantom{..................}\\ \backslash\phantom{.............}\\ \ce{CH-O-CH3}\\ /\phantom{..............}\\ \ce{CH3}\phantom{..................} \end{array}\] |
(b) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-I + CH3OH}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
| (iii) | \[\begin{array}{cc} \ce{CH3}\phantom{.}\\ |\phantom{....}\\ \ce{H3C-C-O-CH3}\\ |\phantom{....}\\ \ce{CH3}\phantom{..} \end{array}\] |
(c) | ![]() |
| (iv) | ![]() |
(d) | CH3—OH + CH3—I |
| (e) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-OH + CH3I}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (f) | \[\begin{array}{cc} \ce{CH3}\phantom{.....................}\\ \backslash\phantom{.................}\\ \ce{CH-I + CH3OH}\\ /\phantom{.................}\\ \ce{CH3}\phantom{.....................} \end{array}\] |
||
| (g) | \[\begin{array}{cc} \ce{CH3}\phantom{....}\\ |\phantom{.......}\\ \ce{CH3-C-OH + CH3I}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
Explain why Lewis acid is not required in bromination of phenol?
The IUPAC name of
is ______.



