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प्रश्न
What is the resistance between A and B in the figure given below?
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उत्तर
The resistors of values 20 Ω, 10 Ω and 20 Ω are connected in series.
Therefore, their net resistance is:
R = 20 Ω + 10 Ω + 20 Ω
R = 50 Ω
This combination of resistors is connected in parallel with that of value 30 Ω.
Therefore, the resistance R' is:
`1/(R') = 1/50 + 1/30`
`1/(R') = (3 + 5)/150`
R' = `150/8`
R' = 18.75 Ω
The resistance, R' is connected in series with the two resistors of values 10 Ω each. Hence, the total resistance between A and B is:
18.75 + 10 + 10 = 38.75 Ω
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