Advertisements
Advertisements
प्रश्न
What is the action of the following reagents on glucose?
acetic anhydride
Advertisements
उत्तर
Glucose reacts with acetic anhydride to form glucose pentaacetate.
APPEARS IN
संबंधित प्रश्न
Write the name of the polysaccharide used for the commercial preparation of glucose.
What is monosaccharide?
Which of the following is the basic unit of carbohydrates?
Formation of lactose by conden ation results in the release of how many molecules of water?
From the following identify the materials that are made up of cellulose.
i. Plant cell wall
ii. Exoskeleton of arthropods
iii. Paper from plant pulp
iv. Cotton fibre
All these carbohydrates contain \[\ce{1 -> 4β}\] glycosidic linkage, EXCEPT ____________.
Which element among the following is not present in saccharine?
Which one of the following is an oligosaccharide?
The general formula for polysaccharide is ____________.
Stachyose is ____________.
Which one of the following is a carbohydrate but does NOT follow the general formula of carbohydrate?
When 2 moles of stachyose is hydrolyzed, the number of moles of galactose obtained is ____________.
Identify the product Y in the following reaction.
\[\ce{Maltose ->[Hydrolysis] X ->[dil. HNO3][(excess)] Y}\]
How many hydroxyl groups are present in Erythrulose?
Which among the following observations suggests that glucose also exists in cyclic form?
Complete hydrolysis of cellulose gives ____________.
Why carbohydrates are generally optically active?
The molecule of glucose is also called ______.
The two monosaccharides in a disaccharide are held together by ______ bonds.
Consider the following reaction
\[\ce{A <-[Br2 - H2O] Glucose ->[HNO3] B}\]
Here, 'A' and 'B' are respectively.
Why carbohydrates are generally optically active.
Why carbohydrates are generally optically active?
Why carbohydrates are generally optically active.
\[\ce{CH2OH-CO-(CHOH)4-CH2OH}\] is an example of ______.
Why carbohydrates are generally optically active.
