Advertisements
Advertisements
प्रश्न
Why carbohydrates are generally optically active?
Advertisements
उत्तर
Carbohydrates are generally optically active because they have one or more chiral carbon atoms in their molecules. For example, Glucose has four chiral carbons and therefore it is optically active.
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\phantom{...}\ce{CH2OH}
\end{array}\]
\[\ce{^*C}\] - Chiral carbon
APPEARS IN
संबंधित प्रश्न
What is the action of the following reagents on glucose?
hydrogen iodide
Write a commercial method for preparation of glucose.
Which of the following type of carbohydrates cannot be hydrolyzed?
Identify the bond that links the carbon of two adjacent monosaccharides.
Which one of the following is a carbohydrate but does NOT follow the general formula of carbohydrate?
Which of the following statement is NOT true about saccharic acid?
What is the molecular formula of glyceraldehyde?
Which among the following reagents is used to obtain gluconic acid from glucose?
\[\ce{Glucose ->[(HCN)] Product ->[(hydrolysis)] Product ->[(HI + Heat)] A}\], the compound A is:
CH2 OH - CO - (CHOH)4 - CH2 OH is an example of ______.
