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प्रश्न
Why carbohydrates are generally optically active?
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उत्तर
Carbohydrates are generally optically active because they have one or more chiral carbon atoms in their molecules. For example, Glucose has four chiral carbons and therefore it is optically active.
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\ce{^*CHOH}\\
|\phantom{....}\\
\phantom{...}\ce{CH2OH}
\end{array}\]
\[\ce{^*C}\] - Chiral carbon
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संबंधित प्रश्न
Explain the preparation of glucose from sucrose.
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When 2 moles of stachyose is hydrolyzed, the number of moles of galactose obtained is ____________.
Which among the following observations suggests that glucose also exists in cyclic form?
Which one of the following rotates the plane polarized light towards left?
What are reducing and non-reducing sugars?
Why carbohydrates are generally optically active.
