Advertisements
Advertisements
प्रश्न
Using the following data, draw time - displacement graph for a moving object:
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| Displacement (m) | 0 | 2 | 4 | 4 | 4 | 6 | 4 | 2 | 0 |
Use this graph to find average velocity for the first 4 s, for the next 4 s and for the last 6 s.
Advertisements
उत्तर
From the given data, the displacement-time graph is shown as

Average velocity = `("Change in displacement")/("time interval")`
∴ For first 4s, v1 = `(4 - 0)/4`
= 1 ms−1
For next 4s v2 = `(4 - 4)/4`
= 0 ms−1
For last 6s v3 = `(0 - 6)/6`
= −1 ms−1
APPEARS IN
संबंधित प्रश्न
An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
The displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero ? Give reason for your answer.
Define displacement. State its unit.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line parallel to the time axis?
From the displacement-time graph of a cyclist given below in the Figure, find The displacement from the initial position at the end of 10 s,

Figure (a) shows the velocity-time graph for the motion of a body. Use it to find the displacement of the body at t = 1 s, 2 s, 3 s and 4 s, then draw on Figure (b), the displacement-time graph for it.
![]() |
![]() |
| (a) | (b) |
Calculate the distance and displacement in the following case:
The graph shows how the velocity of a scooter varies with time in 50 s.
Work out: The distance traveled in 10 s, 20 s, and 50 s.
Obtain a relation for the distance travelled by an object moving with uniform acceleration in the interval between 4th and 5th seconds.
Choose the correct option.


