Advertisements
Advertisements
प्रश्न
Using the following data, draw time - displacement graph for a moving object:
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| Displacement (m) | 0 | 2 | 4 | 4 | 4 | 6 | 4 | 2 | 0 |
Use this graph to find average velocity for the first 4 s, for the next 4 s and for the last 6 s.
Advertisements
उत्तर
From the given data, the displacement-time graph is shown as

Average velocity = `("Change in displacement")/("time interval")`
∴ For first 4s, v1 = `(4 - 0)/4`
= 1 ms−1
For next 4s v2 = `(4 - 4)/4`
= 0 ms−1
For last 6s v3 = `(0 - 6)/6`
= −1 ms−1
APPEARS IN
संबंधित प्रश्न
The displacement of a moving object in a given interval of time is zero. Would the distance travelled by the object also be zero ? Give reason for your answer.
A particle is moving in a circular path of radius r. The displacement after half a circle would be :
Define displacement. State its unit.
Can displacement-time sketch be parallel to the displacement axis? Give a reason to your answer.
A body starts with an initial velocity of 10m s-1 and acceleration 5 m s-2. Find the distance covered by it in 5 s.
Under what condition is the displacement of a body equal to the distance traveled by it?
A body moves along a circular path of radius r. When it completes three complete rounds, what is the ratio of distance covered to its displacement?
The shortest distance between two places is ______.
Distance travelled by a body in a given time ______.
A quantity that has both magnitude and direction is ______.
