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प्रश्न
Using the following data, draw time - displacement graph for a moving object:
| Time (s) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
| Displacement (m) | 0 | 2 | 4 | 4 | 4 | 6 | 4 | 2 | 0 |
Use this graph to find average velocity for the first 4 s, for the next 4 s and for the last 6 s.
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उत्तर
From the given data, the displacement-time graph is shown as

Average velocity = `("Change in displacement")/("time interval")`
∴ For first 4s, v1 = `(4 - 0)/4`
= 1 ms−1
For next 4s v2 = `(4 - 4)/4`
= 0 ms−1
For last 6s v3 = `(0 - 6)/6`
= −1 ms−1
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संबंधित प्रश्न
Can displacement-time sketch be parallel to the displacement axis? Give a reason to your answer.
What can you say about the nature of motion of a body if its displacement-time graph is A straight line inclined to the time axis with an obtuse angle?
How is the distance related with time for motion under uniform acceleration such as the motion of a freely falling body?
A body is moving in a straight line and its displacement at various instants of time is given in the following table
| Time (s) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Displacement (m) | 2 | 6 | 12 | 12 | 12 | 18 | 22 | 24 |
Plot the displacement-time graph and calculate
(i) Total distance travelled in the interval 1 s to 5 s.
(ii) Average velocity in time interval 1 s to 5 s.
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Give the name of the physical quantity that corresponds to the rate of change of displacement.
Name the physical quantity associated with the rate of change of displacement with time.
Four cars A, B, C, and D are moving on a levelled road. Their distance versus time graphs are shown in Fig. 8.2. Choose the correct statement.

Distance travelled by a freely falling body is proportional to ______.
