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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following: [CoFX6]X3−,[Co(HX2O)X6]X2

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प्रश्न

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

\[\ce{[CoF6]^{3-}, [Co(H2O)6]^{2+}, [Co(Cn)6]^{3-}}\]

दीर्घउत्तर
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उत्तर

(1) \[\ce{[CoF6]^{3-}}\]:

\[\ce{Co^{3+} = 3d^6}\]

Number of unpaired electrons = 4

Magnetic moment = `sqrt(n(n + 2)) = sqrt(4(4 + 2))` = 4.9 BM

(ii) \[\ce{[Co(H2O)6]^{2+}}\]: 

\[\ce{Co^{2+} = 3d^7}\]

Number of unpaired electrons = 3

Magnetic moment = `sqrt(3(3 + 2))` = 3.87 BM

(iii) \[\ce{[Co(CN)6]^{3-}}\]:

\[\ce{Co^{3+} = 3d^6}\]

No unpaired electrons so diamagnetic. 

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अध्याय 9: Coordination Compounds - Exercises [पृष्ठ १२७]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 9 Coordination Compounds
Exercises | Q VI. 46. (i) | पृष्ठ १२७

संबंधित प्रश्न

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(i) \[\ce{[Co(NH3)6]^{3+}}\]

(ii) \[\ce{[Mn(CN)6]^{3-}}\] 

(iii) \[\ce{[Fe(CN)6]^{4-}}\]

(iv) \[\ce{[Fe(CN)6]^{3-}}\]


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(i) \[\ce{[MnCl6]^{3-}}\]

(ii) \[\ce{[FeF6]^{3-}}\]

(iii) \[\ce{[CoF6]^{3-}}\]

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\[\ce{[Cr(Cl)6]^{3-}, [Cr(CN)6]^{3-}, [Cr(NH3)6]^{3+}}\].


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Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

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