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Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following: [CoFX6]X3−,[Co(HX2O)X6]X2 - Chemistry

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प्रश्न

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

\[\ce{[CoF6]^{3-}, [Co(H2O)6]^{2+}, [Co(Cn)6]^{3-}}\]

दीर्घउत्तर
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उत्तर

(1) \[\ce{[CoF6]^{3-}}\]:

\[\ce{Co^{3+} = 3d^6}\]

Number of unpaired electrons = 4

Magnetic moment = `sqrt(n(n + 2)) = sqrt(4(4 + 2))` = 4.9 BM

(ii) \[\ce{[Co(H2O)6]^{2+}}\]: 

\[\ce{Co^{2+} = 3d^7}\]

Number of unpaired electrons = 3

Magnetic moment = `sqrt(3(3 + 2))` = 3.87 BM

(iii) \[\ce{[Co(CN)6]^{3-}}\]:

\[\ce{Co^{3+} = 3d^6}\]

No unpaired electrons so diamagnetic. 

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अध्याय 9: Coordination Compounds - Exercises [पृष्ठ १२७]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 9 Coordination Compounds
Exercises | Q VI. 46. (i) | पृष्ठ १२७

संबंधित प्रश्न

On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.


State the superiority of crystal field theory over valence bond theory.


The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, \[\ce{[Co(NH3)6]^{3+}}\], \[\ce{[Co(CN)6]^{3-}}\], \[\ce{[Co(H2O)6]^{3+}}\]


The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.


Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?

(i) \[\ce{[MnCl6]^{3-}}\]

(ii) \[\ce{[FeF6]^{3-}}\]

(iii) \[\ce{[CoF6]^{3-}}\]

(iv) \[\ce{[Ni(NH3)6]^{2+}}\]


Give the electronic configuration of the following complexes on the basis of Crystal Field Splitting theory.

\[\ce{[CoF6]^{3-}, [Fe(CN)6]^{4-} and [Cu(NH3)6]^{2+}}\].


Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

The CFSE for octahedral [CoCl6]−4 is 18,000 cm−1. What will be the CFSE for tetrahedral [CoCl3]−2?


[Ni(H2O)6]2+ (aq) is green in colour whereas [Ni(H2O)4 (en)]2+ (aq)is blue in colour, give reason in support of your answer.


The correct order of increasing crystal field strength in following series:


The magnitude of CFSE depends upon ______


The CFSE of [CoCl6]3– is 18000 cm–1 the CFSE for [CoCl4] will be ______.


What is crystal field splitting energy?


For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements:

  1. Both the complexes can be high spin.
  2. Ni(II) complex can very rarely below spin.
  3. With strong field Ligands, Mn(II) complexes can be low spin.
  4. Aqueous solution of Mn (II) ions is yellow in colour.

The correct statements are:


Consider that d6 metal ion (M2+) forms a complex with aqua ligands and the spin only magnetic moment of the complex is 4.90 BM. The geometry and the crystal field stabilization energy of the complex are ______.


The complex that has highest crystal field splitting energy (Δ) is ______.


On the basis of Crystal Field theory, write the electronic configuration for the d5 ion with a strong field ligand for which Δ0 > P.


On the basis of Crystal Field Theory, write the electronic configuration of d4 ion if Δ0 > P.


The correct order of the wavelength of light absorbed by the following complexes is:

  1. [Co(NH3)6]3+
  2. [Co(CN)6]3−
  3. [Cu(H2O)4]2+
  4. [Ti(H2O)6]3+

Choose the correct answer from the options given below:


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