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The Line Through (H, 3) and (4, 1) Intersects the Line 7x − 9y − 19 = 0 at Right Angle. Find the Value of H.

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प्रश्न

The line through (h, 3) and (4, 1) intersects the line 7x − 9y − 19 = 0 at right angle. Find the value of h.

संक्षेप में उत्तर
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उत्तर

Let A (h,3) and B (4,1) be the given points.
The line 7x − 9y − 19 = 0 can be written as \[y = \frac{7}{9}x - \frac{19}{9}\]

 So, the slope of this line is \[\frac{7}{9}\] 

It is given that the line joining the points (h,3) and (4,1) is perpendicular to the line 7x − 9y − 19 = 0.

\[\frac{7}{9} \times \frac{1 - 3}{4 - h} = - 1\]

\[ \Rightarrow 9h - 36 = - 14\]

\[ \Rightarrow 9h = 22\]

\[ \Rightarrow h = \frac{22}{9}\] 

Hence, the value of h is \[\frac{22}{9}\].

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अध्याय 23: The straight lines - Exercise 23.12 [पृष्ठ ९३]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.12 | Q 19 | पृष्ठ ९३

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