हिंदी

The equation of the line passing through (1, 2) and perpendicular to x + y + 7 = 0 is ______.

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प्रश्न

The equation of the line passing through (1, 2) and perpendicular to x + y + 7 = 0 is ______.

विकल्प

  • y – x + 1 = 0

  • y – x – 1 = 0

  • y – x + 2 = 0

  • y – x – 2 = 0.

MCQ
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उत्तर

The equation of the line passing through (1, 2) and perpendicular to x + y + 7 = 0 is y – x – 1 = 0.

Explanation:

. Let the slope of the line be m.

Then, its equation passing through (1, 2) is given by

y – 2 = m(x – 1)  ....(1)

Again, this line is perpendicular to the given line x + y + 7 = 0 whose slope is – 1 (Why?)

Therefore, we have m ( – 1) = – 1

or m = 1

Hence, the required equation of the line is obtained by putting the value of m in (1)

i.e., y – 2 = x – 1

or y – x – 1 = 0

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अध्याय 10: Straight Lines - Solved Examples [पृष्ठ १७४]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 10 Straight Lines
Solved Examples | Q 14 | पृष्ठ १७४

वीडियो ट्यूटोरियलVIEW ALL [1]

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