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The Force Exerted by the Floor of an Elevator on the Foot of a Person is More than the Weight of the Person If the Elevator is

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प्रश्न

The force exerted by the floor of an elevator on the foot of a person is more than the weight of the person if the elevator is
(a) going up and slowing down
(b) going up and speeding up
(c) going down and slowing down
(d) going down and speeding up

योग
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उत्तर

(b) going up and speeding up
(c) going down and slowing down
It means normal force exerted by the floor of the elevator on the person is greater that the weight of the person.
i.e. N > mg

(i) Going up and speeding up:
aeff = g + a
N = maeff = mg + ma (N > mg)

(ii) Going down and speeding up:
aeff = g – a
N = mg – ma (N < mg)

(iii) Going down and slowing down:
aeff = g – (–a) = g + a
N = mg + ma (N > mg)

 (iv) Going up and slowing down:
 aeff = g – a
  N = mg – ma (N < mg)

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अध्याय 5: Newton's Laws of Motion - MCQ [पृष्ठ ७९]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 5 Newton's Laws of Motion
MCQ | Q 6 | पृष्ठ ७९

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