हिंदी

If non-parallel sides of a trapezium are equal, prove that it is cyclic.

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प्रश्न

If non-parallel sides of a trapezium are equal, prove that it is cyclic.

योग
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उत्तर

Given:

ABCD is a trapezium whose non-parallel sides AD and BC are equal.

Trapezium ABCD is cyclic.

Join BE, where BE || AD

Proof: Since, AB || DE and AD || BE

Since the quadrilateral ABED is a parallelogram.

∴ ∠BAD = ∠BED    ...(i)   [Opposite angles of a parallelogram are equal]

And AD = BE        ...(ii)   [Opposite angles of a parallelogram are equal]

But AD = BC    [Given]   ...(iii)

From equations (ii) and (iii)

BC = BE

⇒ ∠BEC = ∠BCE    ...(iv)  [Angles opposite to equal sides are equal]

Also, ∠BEC + ∠BED = 180°   ...[Linear pair axiom]

∴ ∠BCE + ∠BAD = 180°     ...[From equations (i) and (iv)]

If the sum of opposite angles of a quadrilateral is 180°, then the quadrilateral is cyclic.

Hence, trapezium ABCD is cyclic.

Hence proved.

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अध्याय 10: Circles - Exercise 10.4 [पृष्ठ १०६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 9
अध्याय 10 Circles
Exercise 10.4 | Q 2. | पृष्ठ १०६
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नूतन Mathematics [English] Class 10 ICSE
अध्याय 15 Circles
Exercise 15A | Q 52. | पृष्ठ ३३६

वीडियो ट्यूटोरियलVIEW ALL [3]

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