Advertisements
Advertisements
प्रश्न
ABCD is a cyclic quadrilateral such that ∠ADB = 30° and ∠DCA = 80°, then ∠DAB =
विकल्प
70°
100°
125°
150°
Advertisements
उत्तर
70°
It is given that ABCD is cyclic quadrilateral ∠ADB = 90° and ∠DCA = 80°. We have to find ∠DAB
We have the following figure regarding the given information
∠BDA = ∠BCA = 30° (Angle in the same segment are equal)
Now, since ABCD is a cyclic quadrilateral
So, ∠DAB + ∠BCD = 180°
`angleDAB + angleBCA + angleDCA` = 180°
`angleDAB ` + 30° + 80° = 180°
`angleDAB` = 180° - 110°
`angleDAB ` = 70 °
APPEARS IN
संबंधित प्रश्न
A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.
If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side.
Two congruent circles intersect each other at points A and B. Through A any line segment PAQ is drawn so that P, Q lie on the two circles. Prove that BP = BQ.
ABCD is a cyclic quadrilateral in ∠BCD = 100° and ∠ABD = 70° find ∠ADB.
ABCD is a cyclic trapezium with AD || BC. If ∠B = 70°, determine other three angles of the trapezium.
ABCD is a cyclic quadrilateral in which BA and CD when produced meet in E and EA = ED. Prove that AD || BC .
In the given figure, O is the centre of the circle such that ∠AOC = 130°, then ∠ABC =
ABCD is a cyclic quadrilateral. M (arc ABC) = 230°. Find ∠ABC, ∠CDA, and ∠CBE.
In a cyclic quadrilaterals ABCD, ∠A = 4x, ∠C = 2x the value of x is
If a pair of opposite sides of a cyclic quadrilateral are equal, prove that its diagonals are also equal.
