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प्रश्न
Identify the activity of endonuclease and exonuclease in the given image.
विकल्प
Endonuclease Exonuclease 
Endonuclease Exonuclease 
Endonuclease Exonuclease 
Endonuclease Exonuclease 
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उत्तर
| Endonuclease | Exonuclease |
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|
Explanation:
Endonucleases are a type of restriction enzyme that cuts the DNA at a specified location. It is widely used to clip the sequence in order to obtain DNA fragments with sticky ends. Sticky ends are single-stranded DNA segments that can establish hydrogen bonds with adjacent cut DNA segments. The enzyme ligase later joins these ends. Exonuclease is a restriction enzyme that removes nucleotides from the 5' and 3' ends of DNA strands.
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संबंधित प्रश्न
Name and describe the technique that helps in separating the DNA fragments formed by the use of restriction endonuclease
Explain briefly:
Restriction enzymes and DNA
Distinguish between exonuclease and endonuclease.
The total number of nucleotide sequences of DNA that code for a hormone is 1530. The proportion of different bases in the sequence is found to be Adenine = 34%, Guanine = 19%, Cytosine = 23%, Thymine = 19%.
Applying Chargaff’s rule, what conclusion can be drawn?
Which of the following radioisotope is not suitable for DNA labeling based studies?
Which of the following enzymes catalyse the removal of nucleotides from the ends of DNA?
Which of the following bacteria is not a source of restriction endonuclease?
Restriction enzymes that are used in the construction of recombinant DNA are endonucleases which cut the DNA at ‘specific-recognition sequence’. What would be the disadvantage if they do not cut the DNA at specific-recognition sequence?
CTTAAG
GAATTC
- What are such sequences called? Name the enzyme used that recognizes such nucleotide sequences.
- What is their significance in biotechnology?
Carefully observe the given picture. A mixture of DNA with fragments ranging from 200 base pairs to 2500 base pairs was electrophoresed on agarose gel with the following arrangement.
(a) What result will be obtained on staining with ethidium bromide? Explain with reason.
(b) The above setup was modified and a band with 250 base pairs was obtained at X.
What change(s) were made to the previous design to obtain a band at X? Why did the band appear at position X?
