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For a transistor IC = 15 mA, IB = 0.5 mA. What is the current amplification factor? - Physics

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प्रश्न

For a transistor IC = 15 mA, IB = 0.5 mA. What is the current amplification factor?  

योग
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उत्तर

Current amplification factor, β = `("I"_"c")/("I"_"B") = 15/0.5 = 30`

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Bipolar Junction Transistor (BJT)
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अध्याय 16: Semiconductors Devices - Very Short Answer

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