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Find the differential equation of the ellipse whose major axis is twice its minor axis. - Mathematics and Statistics

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प्रश्न

Find the differential equation of the ellipse whose major axis is twice its minor axis.

योग
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उत्तर

Let 2a and 2b be lengths of major axis and minor axis of the ellipse.

Then 2a = 2(2b)

∴ a = 2b

∴ equation of the ellipse is

`"x"^2/"a"^2 + "y"^2/"b"^2 = 1`

i.e. `"x"^2/(2"b")^2 + "y"^2/"b"^2 = 1`

∴ `"x"^2/(4"b"^2) + "y"^2/"b"^2 = 1`

∴ x2 + 4y2 = 4b2 

Differentiating w.r.t. x, we get

`"2x" + 4 xx "2y" "dy"/"dx" = 0`

∴ `"x" + "4y" "dy"/"dx" = 0`

This is the required D.E.

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अध्याय 6: Differential Equations - Miscellaneous exercise 2 [पृष्ठ २१७]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Miscellaneous exercise 2 | Q 4.3 | पृष्ठ २१७
बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Exercise 6.2 | Q 4 | पृष्ठ १९६

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