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Obtain the differential equation by eliminating the arbitrary constants from the following equation: (y - a)2 = 4(x - b) - Mathematics and Statistics

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प्रश्न

Obtain the differential equation by eliminating the arbitrary constants from the following equation:

(y - a)2 = 4(x - b)

योग
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उत्तर

(y - a)2 = 4(x - b)

Differentiating twice w.r.t. x, we get

`2 ("y - a")*"d"/"dx"("y - a") = 4 "d"/"dx" ("x - b")`

∴ `2 ("y - a")*("dy"/"dx" - 0) = 4(1 - 0)`

∴ `2 ("y - a")"dy"/"dx" = 4`

∴ `("y - a")"dy"/"dx" = 2`     ....(1)

Differentiating again w.r.t. x, we get

`("y - a")"d"/"dx" ("dy"/"dx") + "dy"/"dx"*"d"/"dx" ("y - a") = 0`

∴ `("y - a")("d"^2"y")/"dx"^2 + "dy"/"dx" * ("dy"/"dx" - 0) = 0`

∴ `("y - a")("d"^2"y")/"dx"^2 + ("dy"/"dx")^2 = 0`

∴ `2/("dy"/"dx") * ("d"^2"y")/"dx"^2 + ("dy"/"dx")^2 = 0`      .....[By (1)]

∴ `2 ("d"^2"y")/"dx"^2 + ("dy"/"dx")^3 = 0`

This is the required D.E.

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Formation of Differential Equations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Differential Equations - Exercise 6.2 [पृष्ठ १९६]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Exercise 6.2 | Q 1.06 | पृष्ठ १९६

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