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Obtain the differential equation by eliminating the arbitrary constants from the following equation: y = a + axax

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प्रश्न

Obtain the differential equation by eliminating the arbitrary constants from the following equation:

y = a + `"a"/"x"`

योग
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उत्तर

y = a + `"a"/"x"`    ....(1)

Differentiating twice w.r.t. x, we get

`"dy"/"dx" = "d"/"dx"("a" + "a"/"x") = 0 + "a"(- 1/"x"^2)`

∴ `"dy"/"dx" = - "a"/"x"^2`

∴ `"a" = - "x"^2 "dy"/"dx"`

Substituting the value of a in (1), we get

y = - `"x"^2 "dy"/"dx" + 1/"x"(- "x"^2 "dy"/"dx")`

∴ y = -`"x"^2  "dy"/"dx" - "x" "dy"/"dx"`

∴ `("x"^2 + "x") "dy"/"dx" + "y" = 0`

∴ x(x + 1) `"dy"/"dx" + "y" = 0`

This is the required D.E.

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Notes

The answer in the textbook is incorrect.

  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Differential Equations - Exercise 6.2 [पृष्ठ १९६]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 6 Differential Equations
Exercise 6.2 | Q 1.07 | पृष्ठ १९६

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