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प्रश्न
Find the differential equation from the relation x2 + 4y2 = 4b2
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उत्तर
x2 + 4y2 = 4b2 ......(i)
Here, b is an arbitrary constant.
Differentiating w.r.t. x, we get
`2x + 4(2y ("d"y)/("d"x))` = 0
∴ `x + 4y ("d"y)/("d"x)` = 0
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